Find The Quadratic Equation Whose Roots Are (3 2013 J5) & (2 + J4).

Find the quadratic equation whose roots are (3 – j5) & (2 + j4).

 

Answer:

x² -6x + jx - 3j + 9

Step-by-step explanation:

Find the quadratic equation whose roots are (3 – j5) & (2 + j4).

x - (3 - j^5) × x - (2+ j4)

= x - 3 + j^5) × x - 2 - j^4)

j² = -1 (j ⇒ imaginary number

j^4 = 1

j^5 = j

= x - 3 + j) × x - 2 - 1)

= x - 3 + j) × x - 3)

= x² -3x - 3x + 9 + jx -3j

combine like terms

=  x² -6x + jx - 3j + 9


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