Find The Quadratic Equation Whose Roots Are (3 2013 J5) & (2 + J4).
Find the quadratic equation whose roots are (3 – j5) & (2 + j4).
Answer:
x² -6x + jx - 3j + 9
Step-by-step explanation:
Find the quadratic equation whose roots are (3 – j5) & (2 + j4).
x - (3 - j^5) × x - (2+ j4)
= x - 3 + j^5) × x - 2 - j^4)
j² = -1 (j ⇒ imaginary number
j^4 = 1
j^5 = j
= x - 3 + j) × x - 2 - 1)
= x - 3 + j) × x - 3)
= x² -3x - 3x + 9 + jx -3j
combine like terms
= x² -6x + jx - 3j + 9
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